1
AP EAPCET 2022 - 4th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

A car travels with a speed of $$40 \mathrm{~km} \mathrm{~h}^{-1}$$. Rain drops are falling at a constant speed vertically. The traces of the rain on the side windows of the car make an angle of $$30^{\circ}$$ with the vertical. The magnitude of the velocity of the rain with respect to the car is

A
$$40 \sqrt{3} \mathrm{~km} \mathrm{~h}^{-1}$$
B
$$\frac{40}{\sqrt{3}} \mathrm{~km} \mathrm{~h}^{-1}$$
C
$$80 \mathrm{~km} \mathrm{~h}^{-1}$$
D
$$\frac{80}{\sqrt{3}} \mathrm{~km} \mathrm{~h}^{-1}$$
2
AP EAPCET 2022 - 4th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

A projectile with speed $$50 \mathrm{~ms}^{-1}$$ is thrown at an angle of $$60^{\circ}$$ with the horizontal. The maximum height that can be reached is (acceleration due to gravity $$=10 \mathrm{~ms}^{-2}$$)

A
90.75 m
B
70.00 m
C
85.00 m
D
93.75 m
3
AP EAPCET 2021 - 20th August Morning Shift
MCQ (Single Correct Answer)
+1
-0

A boy throws a cricket ball from the boundary to the wicket keeper. If the frictional force due to air $$(f_a )$$ cannot be ignored, the forces acting on the ball at the position X are represented by

AP EAPCET 2021 - 20th August Morning Shift Physics - Motion in a Plane Question 5 English

A
AP EAPCET 2021 - 20th August Morning Shift Physics - Motion in a Plane Question 5 English Option 1
B
AP EAPCET 2021 - 20th August Morning Shift Physics - Motion in a Plane Question 5 English Option 2
C
AP EAPCET 2021 - 20th August Morning Shift Physics - Motion in a Plane Question 5 English Option 3
D
AP EAPCET 2021 - 20th August Morning Shift Physics - Motion in a Plane Question 5 English Option 4
4
AP EAPCET 2021 - 19th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle of mass m is projected with a velocity u making an angle $$\theta$$ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height is

A
0
B
$$\frac{m u \sin ^2 \theta \cos \theta}{2 g}$$
C
$$\frac{2 m u^2 \cos ^2 \theta \sin \theta}{g}$$
D
$$\frac{m u^3 \sin ^2 \theta \cos \theta}{2 g}$$
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