1
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\cos ^3 80^{\circ}+\cos ^3 40^{\circ}-\cos ^3 20^{\circ}=k$, then $\frac{4 k}{3}=$

A

$\sin \left(\frac{4 \pi}{3}\right)$

B

$\cos \left(\frac{2 \pi}{3}\right)$

C

$\tan \left(\frac{\pi}{3}\right)$

D

$\sec \left(\frac{2 \pi}{3}\right)$

2
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \cos 13^{\circ} \sin 17^{\circ} \sin 21^{\circ} \cos 47^{\circ}= $$

A

$\frac{1}{32}(1+\sqrt{2}-\sqrt{3})$

B

$\frac{1}{16}(1+\sqrt{3}+\sqrt{5})$

C

$\frac{1}{16}(2+\sqrt{3}-\sqrt{5})$

D

$\frac{1}{32}(1+2 \sqrt{3}-\sqrt{5})$

3
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$$ \sin \frac{\pi}{5}+\sin \frac{2 \pi}{5}+\sin \frac{3 \pi}{5}+\sin \frac{4 \pi}{5}= $$
A

1

B

$\sqrt{5}$

C

$\frac{1}{4}(\sqrt{5}+1)(\sqrt{10+2 \sqrt{5}})$

D

$\frac{1}{4}(\sqrt{5}-1)(\sqrt{10+2 \sqrt{5}})$

4
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$\operatorname{cosec} 48^{\circ}+\operatorname{cosec} 96^{\circ}+\operatorname{cosec} 192^{\circ}+\operatorname{cosec} 384^{\circ}=$

A

$4 \sqrt{3}$

B

$-4 \sqrt{3}$

C

0

D

1

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