1
AP EAPCET 2021 - 19th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

A discrete random variable X takes values 10, 20, 30 and 40. with probability 0.3, 0.3, 0.2 and 0.2 respectively. Then the expected value of X is

A
12
B
22
C
23
D
24
2
AP EAPCET 2021 - 19th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $$X$$ be a random variable which takes values $$1,2,3,4$$ such that $$P(X=r)=K r^3$$ where $$r=1,2,3,4$$ then

A
$$K=\frac{1}{100}$$ and $$P\left(\frac{1}{2} < X<\frac{5}{2} \mid X > 1\right)=\frac{8}{97}$$
B
$$K=\frac{1}{99}$$ and $$P\left(\frac{1}{2} < X < \frac{5}{2} \mid X > 1\right)=\frac{8}{99}$$
C
$$K=\frac{1}{100}$$ and $$P\left(\frac{1}{2} < X < \frac{5}{2} \mid X > 1\right)=\frac{8}{99}$$
D
$$K=\frac{1}{100}$$ and $$P\left(\frac{1}{2} < X <\frac{5}{2} \mid X >1\right)=\frac{10}{99}$$
3
AP EAPCET 2021 - 19th August Morning Shift
MCQ (Single Correct Answer)
+1
-0

12 balls are distributed among 3 boxes, then the probability that the first box will contain 3 balls is

A
$$\frac{{ }^{12} C_3 \times 2^9}{3^{12}}$$
B
$$\frac{{ }^{12} C_3 \times 2^9}{3^{10}}$$
C
$$\frac{{ }^{12} C_3}{3^{12}}$$
D
$$\frac{{ }^{12} C_3}{3^{10}}$$
4
AP EAPCET 2021 - 19th August Morning Shift
MCQ (Single Correct Answer)
+1
-0

A random variable X has the probability distribution

X 1 2 3 4 5 6 7 8
P(X) 0.15 0.23 0.12 0.10 0.20 0.08 0.07

For the events E = {X is a prime number} and F = {X < 4}, then P(E $$\cup$$ F) is

A
0.77
B
0.87
C
0.35
D
0.50
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