1
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A body of mass 1 kg is attached to the lower end of a vertically suspended spring of force constant $600 \mathrm{~N}-\mathrm{m}^{-1}$. If another body of mass 0.5 kg moving vertically upward hits the suspended body with a velocity $3 \mathrm{~ms}^{-1}$ and embedded in it, then the frequency of the oscillation is

A

$\frac{5}{\pi} \mathrm{~Hz}$

B

$\frac{10}{\pi} \mathrm{~Hz}$

C

$\frac{\pi}{5} \mathrm{~Hz}$

D

$\pi \mathrm{Hz}$

2
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the displacement $y$ (in cm ) of a particle executing simple harmonic motion is given by the equation $y=5 \sin (3 \pi t)+5 \sqrt{3} \cos (3 \pi t)$, then the amplitude of the particle is

A

5 cm

B

$5(1+\sqrt{3}) \mathrm{cm}$

C

$5 \sqrt{3} \mathrm{~cm}$

D

10 cm

3
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The angular frequency of a block of mass 0.1 kg oscillating with the help of a spring of force constant $2.5 \mathrm{~N}-\mathrm{m}^{-1}$ is

A

$02 \mathrm{rad} \mathrm{s}^{-1}$

B

$5 \mathrm{rad} \mathrm{s}^{-1}$

C

$10 \mathrm{rad} \mathrm{s}^{-1}$

D

$2 \mathrm{rad} \mathrm{s}^{-1}$

4
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

As shown in the figure, two blocks of masses $m_1$ and $m_2$ are connected to spring of force constant $k$. The blocks are slightly displaced in opposite directions to $x_1, x_2$ distances and released. If the system executes simple harmonic motion, then the frequency of oscillation of the system ( $\omega$ ) is

AP EAPCET 2024 - 23th May Morning Shift Physics - Simple Harmonic Motion Question 20 English
A
$\left(\frac{1}{m_1}+\frac{1}{m_2}\right) k^2$
B
$\sqrt{\left(\frac{1}{m_1}+\frac{1}{m_2}\right) k^2}$
C
$\sqrt{\left(\frac{1}{m_1}+\frac{1}{m_2}\right)}$
D
$\sqrt{\left(\frac{1}{m_1}+\frac{1}{m_2}\right) k}$

AP EAPCET Subjects

Browse all chapters by subject