AP EAPCET 2024 - 23th May Morning Shift | Simple Harmonic Motion Question 2 | Physics

A mass $M$, attached to a horizontal spring executes simple harmonic motion with amplitude $A_1$. When mass $M$ passes mean position, then a smaller mass millis attached to it and both of them together executing simple harmonic motion with amplitude $A_2$. Then, value of $\frac{A_1}{A_2}$ is

$\sqrt{\frac{m^2+M^2}{M^2}}$

$\sqrt{\frac{m+M}{M^2}}$

$\sqrt{\frac{m+M}{M}}$

$$ \text { } \frac{m+M}{M} $$

AP EAPCET 2024 - 22th May Evening Shift

MCQ (Single Correct Answer)

-0

The displacement of a particle of mass 2 g executing simple harmonic motion is $x=8 \cos \left(50 t+\frac{\pi}{12}\right) \mathrm{m}$, where $t$ is time in second. The maximum kinetic energy of the particle is

160 J

80 J

40 J

20 J

AP EAPCET 2024 - 22th May Evening Shift

MCQ (Single Correct Answer)

-0

The relation between the force ( $F$ in Newton) acting on a particle executing simple harmonic motion and the displacement of the particle ( $y$ in metre) is $500 F+\pi^2 y=0$. If the mass of the particle is 2 g . The time period of oscillation of the particle is

8 s

6 s

2 s

4 s

AP EAPCET 2024 - 22th May Morning Shift

MCQ (Single Correct Answer)

-0

Two simple harmonic motions are represented by $y_1=5[\sin 2 \pi t+\sqrt{3} \cos 2 \pi t]$ and $y_2=5 \sin \left[2 \pi t+\frac{\pi}{4}\right]$. The ratio of their amplitudes is

$1: 1$

$2: 1$

$1: 3$

$\sqrt{3}: 1$

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