A bag contains 4 red and 3 black balls. A second bag contains 2 red and 3 black balls. One bag is selected at random. If from the selected bag, one ball is drawn at random, then the probability that the ball drawn is red, is

In a Binomial distribution, if '$$n$$' is the number of trials and the mean and variance are 4 and 3 respectively, then $$2^{32} p\left(X=\frac{n}{2}\right)=$$

For a Poisson distribution, if mean $$=l$$, variance $$=m$$ and $$l+m=8$$, then $$e^4[1-P(X>2)]=$$

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked randomly. The probability that it is neither red nor green is