AP EAPCET 2024 - 19th May Evening Shift | Simple Harmonic Motion Question 18 | Physics

The displacement of a damped oscillator is $x(t)=\exp (-0.2 t) \cos (3.2 t+\phi)$, where $t$ is time in second The time requirement for the amplitude of the oscillator to become $\frac{1}{e^{1.2}}$ times its initial amplitude is

3 s

6 s

2 s

8 s

AP EAPCET 2024 - 18th May Morning Shift

MCQ (Single Correct Answer)

-0

Time period of a simple pendulum in air is $T$. If the pendulum is in water and executes SHM. Its time period is $t$. The value of $\frac{T}{t}$ is. (density of bob is $\frac{5000}{3} \mathrm{~kg} \mathrm{~m}^{-3}$ )

$\frac{2}{5}$

$\sqrt{\frac{2}{5}}$

$\frac{5}{2}$

$\sqrt{\frac{5}{2}}$

AP EAPCET 2024 - 18th May Morning Shift

MCQ (Single Correct Answer)

-0

For a particle executing simple harmonic motion, Match the following statements ( conditions) from Column I to statements (shapes of graph) in Columinit

Column I	Column II
a Velocity-displacement graph $(\omega=1)$	i Straight line
b Acceleration-displacement graph	ii Sinusoidal
c Acceleration - time graph	iii Circle
d Acceleration - velocity $(\omega \neq 1)$	iv Ellipse

a-N, b-i, c-il, d-iif

$\mathrm{a}-\mathrm{in}, \mathrm{b}-\mathrm{i}, \mathrm{c}-\mathrm{i}, \mathrm{d}=\mathrm{k}$

$a=i i, b-1 l, c-1, d-N$

$a-N, b=\bar{c} C=(d-\#$

AP EAPCET 2022 - 5th July Morning Shift

MCQ (Single Correct Answer)

-0

A particle is executing simple harmonic motion with an instantaneous displacement $$x=A \sin ^2\left(\omega t-\frac{\pi}{4}\right)$$. The time period of oscillation of the particle is

$$\frac{2 \pi}{\omega}$$

$$\frac{\pi}{\omega}$$

$$\frac{\pi}{2 \omega}$$

$$\frac{\omega}{2 \pi}$$

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