1
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \sin ^3 10^{\circ}+\sin ^3 50^{\circ}-\sin ^3 70^{\circ}= $$

A

$\frac{-3}{8}$

B

$\frac{3}{4}$

C

$\frac{\sqrt{3}}{2}$

D

$\frac{-1}{3}$

2
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \begin{aligned} \frac{1}{\sin 1^{\circ} \sin 2^{\circ}}+\frac{1}{\sin 2^{\circ} \sin 3^{\circ}}+\frac{1}{\sin 3^{\circ} \sin 4^{\circ}} & +\frac{1}{\sin 89^{\circ} \sin 90^{\circ}}= \end{aligned} $$

A

$\frac{\sin 1^{\circ}}{\tan 1^{\circ}}$

B

$\frac{1}{\sin ^2 \varphi}$

C

$\frac{\cot 1^{\circ}}{\sin 1^{\circ}}$

D

$\frac{\tan 1^{\circ}}{\cos 1^{\circ}}$

3
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \cos ^3 \frac{\pi}{8} \cos \frac{3 \pi}{8}+\sin ^3 \frac{\pi}{8} \sin \frac{3 \pi}{8}= $$

A

$\frac{1}{2 \sqrt{2}}$

B

$\frac{1}{2}$

C

$\frac{1}{\sqrt{2}}$

D

$\frac{1}{4}$

4
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $A+B+C=\frac{\pi}{4}$, then $\sin 4 A+\sin 4 B+\sin 4 C=$

A

$4 \cos 2 A \cos 2 B \cos 2 C$

B

$4 \sin 2 A \sin 2 B \sin 2 C$

C

$1+4 \sin 2 A \sin 2 B \sin 2 C$

D

$1+4 \cos 2 A \cos 2 B \cos 2 C$

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