1
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int \frac{\sec ^2 x}{(\sec x+\tan x)^{\frac{5}{2}}} d x= $$

A

$-\frac{(\sec x+\tan x)^{\frac{5}{2}}}{5}-\frac{(\sec x+\tan x)^{\frac{7}{2}}}{7}+C$

B

$-\frac{(\sec x-\tan x)^{\frac{5}{2}}}{5}-\frac{(\sec x-\tan x)^{\frac{7}{2}}}{7}+C$

C

$-\frac{(\sec x+\tan x)^{\frac{3}{2}}}{3}-\frac{(\sec x+\tan x)^{\frac{7}{2}}}{7}+C$

D

$-\frac{(\sec x-\tan x)^{\frac{3}{2}}}{3}-\frac{(\sec x-\tan x)^{\frac{7}{2}}}{7}+C$

2
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int \frac{1}{\cos x}\left[\frac{1}{\sin x}-\frac{1}{\sin x+3 \cos x}\right] d x= $$

A

$\frac{1}{3} \log \left|\frac{\sin x}{\sin x+3 \cos x}\right|+C$

B

$\log \left|\frac{\cos x}{\sin x+3 \cos x}\right|+c$

C

$\frac{1}{3} \log \left|\frac{\cos x}{\sin x+3 \cos x}\right|+C$

D

$\log \left|\frac{\sin x}{\sin x+3 \cos x}\right|+c$

3
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int \cos ^{-1}\left(\frac{1-x^2}{1+x^2}\right) d x= $$

A

$2\left[x \tan ^{-1} x-\log \sqrt{1+x^2}\right]+C$

B

$2 x \tan ^{-1} x+\log \sqrt{1+x^2}+C$

C

$x \tan ^{-1} x+\log \sqrt{1-x^2}+C$

D

$2\left[\tan ^{-1} x-\log \sqrt{1+x^2}\right]+C$

4
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\frac{a x+5}{\left(x^2+b\right)(x+3)}=\frac{x+21}{12\left(x^2+b\right)}+\frac{c}{12(x+3)}$, then $b^2=$

A

$a^3-c$

B

$a^2+c$

C

$a-c$

D

$a+c$

AP EAPCET Subjects

Browse all chapters by subject