A truss tie consisting of $$2$$ $$ISA$$ $$75 \times 75 \times 8\,\,mm$$ carries a pull of $$150$$ $$kN.$$ At ends the two angles are connected, one each on either side of a $$10$$ $$mm$$ thick gusset plate, by $$18$$ $$mm$$ diameter rivets arranged in one row. The allowable stresses in rivet are $${f_s} = 90.0\,\,N/m{m^2}$$ and $${f_{br}} = 250\,\,N/m{m^2}$$.

Minimum number of rivets required at each end is

$$ISA$$ $$100 \times 100 \times 10\,\,mm$$ (Cross sectional area $$ = 1903\,\,m{m^2})$$ serves as tensile member. This angle is welded to a gusset plate along $$A$$ and $$B$$ appropriately as shown. Assuming the yield strength of the steel to be $$260$$ $$N/m{m^2}$$ the tensile strength of the member can be taken to be approximately

Two steel plates each of width $$150$$ $$mm$$ and thickness $$10$$ $$mm$$ are connected with three $$20$$ $$mm$$ diameter rivets is placed in zig-zag pattern. The pitch of the rivet is $$75$$ $$mm$$ and gauge is $$60$$ $$mm.$$ If the allowable tensile stress is $$150$$ $$MPa,$$ the maximum tensile force that the joint can withstand is