1
GATE EE 2007
MCQ (Single Correct Answer)
+1
-0.3
The common emitter forward current gain of the transistor shown is $${\beta _p} = 100.$$ The transistor is operating in GATE EE 2007 Analog Electronics - Bjt and Mosfet Biasing Question 7 English
A
Saturation region
B
Cut-off region
C
Reverse active region
D
Forward active region
2
GATE EE 2007
MCQ (Single Correct Answer)
+2
-0.6
$$R-L-C$$ circuit shown in figure GATE EE 2007 Control Systems - Time Response Analysis Question 4 English

If the above step response is to be observed on a non - storage $$CRO,$$ then it would be best have the $${e_i}$$ as a

A
step function
B
square wave of $$50$$ $$Hz$$
C
square wave of $$300$$ $$Hz$$
D
square wave of $$2.0$$ $$KHz$$
3
GATE EE 2007
MCQ (Single Correct Answer)
+2
-0.6
The system $$900/s(s+1)(s+9)$$ is to be such that its gain crossover frequency becomes same as its uncompensated phase crossover frequency and provides at $${45^0}$$ phase margin . To achieve this, one may use
A
a lag compensator that provides an attenuation of $$20dB$$ and a phase lag of $${45^0}$$ at the frequency of $$3\sqrt 3 $$ rad/s
B
a lead compensator that provides an amplification of $$20dB$$ and a phase lead of $${45^0}$$ at the frequency of $$3$$ rad/s
C
a lag - lead compensator that provides an amplification of $$20dB$$ and a phase alg of $${45^0}$$ at the frequency of $$\sqrt 3 $$ rad/s
D
a lag - lead compensator that provides an attenuation of $$20dB$$ and phase lead of $${45^0}$$ at the frequency of $$3$$ rad/s
4
GATE EE 2007
MCQ (Single Correct Answer)
+2
-0.6
If $$X = {\mathop{\rm Re}\nolimits} G\left( {j\omega } \right),\,\,$$ and $$y = {\rm I}mG\left( {j\omega } \right)$$ then for $$\omega \to {0^ + },\,\,$$ the Nyquist plot for $$G\left( s \right) = 1/\left[ {s\left( {s + 1} \right)\left( {s + 2} \right)} \right]$$
A
$$x=0$$
B
$$x=-3/4$$
C
$$x=y-1/6$$
D
$$x = y/\sqrt 3 $$
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