R (P, Q, R1, R2, R3)
S (P, Q, S1, S2)
Where {P, Q} is the key for both schemas. Which of the following queries are equivalent?I. $$\Pi_P \left(R \bowtie S\right)$$
II. $$\Pi_P \left(R\right) \bowtie \Pi_P\left(S\right)$$
III. $$\Pi_P \left(\Pi_{P, Q} \left(R\right) \cap \Pi_{P,Q} \left(S\right) \right)$$
IV. $$\Pi_P \left(\Pi_{P, Q} \left(R\right) - \left(\Pi_{P,Q} \left(R\right) - \Pi_{P,Q} \left(S\right)\right)\right)$$
Which of the following tuple relational calculus expression(s) is/are equivalent to $$\forall t \in r \left(P\left(t\right)\right)$$?
I. $$\neg \exists t \in r \left(P\left(t\right)\right)$$II. $$\exists t \notin r \left(P\left(t\right)\right)$$
III. $$\neg \exists t \in r \left(\neg P\left(t\right)\right)$$
IV. $$\exists t \notin r \left(\neg P\left(t\right)\right)$$
Consider The Following Relational Scheme
Student (school-id, sch-roll-no, sname, saddress)
School (school-id, sch-name, sch-address, sch-phone)
Enrolment (school-id, sch-roll-no, erollno, examname)
ExamResult (Erollno, examname, marks)
SELECT sch-name, COUNT (*)
FROM School C, Enrolment E,
ExamResult R
WHERE E.school-id = C.school-id
AND E.examname = R.examname
AND E.erollno = R.erollno
AND R.marks = 100 AND S.school-id IN
(SELECT school-id
FROM student
GROUP BY school-id
HAVING COUNT (*) > 200)
GROUP BY school-id;Consider The Following Relational Scheme
Student (school-id, sch-roll-no, sname, saddress)
School (school-id, sch-name, sch-address, sch-phone)
Enrolment (school-id, sch-roll-no, erollno, examname)
ExamResult (Erollno, examname, marks)
Consider the following tuple relational calculus query
{ t | ∃E ∈ Enrolment t = E.school-id ∧
| { x | x ∈ ExamResult B.school-id =
t ∧ ( ∃B ∈ ExamResult B.erollno =
x.erollno ∧ B.examname = x.examname ∧
B.marks > 35 } | ÷ |
{ x | x ∈ Enrolment ∧ x.school-id = t }
| * 100 > 35 }
If a student needs to score more than 35 marks to pass an exam what does the query return?GATE CSE Papers
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