AP EAPCET 2025 - 23rd May Evening Shift | Simple Harmonic Motion Question 8 | Physics

A spring is stretched by 0.2 m when a mass of 0.5 kg is suspended to it. The time period of the spring when 0.5 kg mass is replaced with a mass of 0.25 kg is suspended to it is

(Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )

0.628 s

6.28 s

62.8 s

0.0628 s

AP EAPCET 2025 - 23rd May Morning Shift

MCQ (Single Correct Answer)

-0

A body of mass 4 kg attached to a spring of force constant $64 \mathrm{Nm}^{-1}$ executes simple harmonic motion on a frictionless horizontal surface. The time period of oscillation is

$\frac{\pi}{3} \mathrm{~s}$

$\frac{\pi}{2} \mathrm{~s}$

$\pi \mathrm{s}$

$\frac{3 \pi}{2} \mathrm{~s}$

AP EAPCET 2025 - 23rd May Morning Shift

MCQ (Single Correct Answer)

-0

A particle is executing simple harmonic motion with amplitude $A$. At a distance ' $x$ ' from the mean position, when the particle is moving towards extreme position it receives a blow in the direction of motion which instantaneously doubles its velocity. The new amplitude of the particle is

(Frequency is constant during the motion)

$A$

$\sqrt{A^2-X^2}$

$\sqrt{2 A^2-3 x^2}$

$\sqrt{4 A^2-3 x^2}$

AP EAPCET 2025 - 22nd May Evening Shift

MCQ (Single Correct Answer)

-0

If the displacement ' $x$ ' of a body in motion in terms of time ' $t$ ' is given by $x=A \sin (\omega t+\theta)$, then the minimum time at which the displacement becomes maximum is

$\left[\frac{\pi}{2 \omega}-\frac{\theta}{\omega}\right]$

$\left[\frac{2 \omega}{\pi}-\frac{\omega}{\theta}\right]$

$\left[\frac{\pi}{\omega}-\frac{1}{\omega}\right]$

$\left[\frac{\omega}{\pi}-\frac{\omega}{\pi^2}\right]$

PREVIOUS NEXT

AP EAPCET Subjects

Browse all chapters by subject