1
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A body of mass 5 kg starts from the origin with an initial velocity $(30 \hat{\mathbf{i}}+40 \hat{\mathbf{j}}) \mathrm{ms}^{-1}$. If a constant force $-(\hat{\mathbf{i}}+5 \hat{\mathbf{j}}) \mathrm{N}$ acts on the body, then the time in which the $y$-component of its velocity becomes zero is

A

5 s

B

20 s

C

40 s

D

80 s

2
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If bullets are fired in all possible directions from same point with equal velocity of $10 \mathrm{~ms}^{-1}$ and with an angle of projection $45^{\circ}$, then the area covered by the bullets on the ground is nearly (Acceleration due to gravity $=10 \mathrm{~m} \mathrm{~s}^{-2}$ )
A

$628 \mathrm{~m}^2$

B

$314 \mathrm{~m}^2$

C

$157 \mathrm{~m}^2$

D

$79 \mathrm{~m}^2$

3
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A ball is projected from a point with a speed $V_0$ at certain angle with the horizontal. From the same point and at the same instant, a person starts running with a constant speed $0.5 V_0$ to catch the ball. If the person catches the ball after some time, then the angle of projection of the ball is

A

$60^{\circ}$

B

$30^{\circ}$

C

$45^{\circ}$

D

$53^{\circ}$

4
AP EAPCET 2024 - 23th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Path of projectile is given by the equation $Y=P x-Q x^2$, match the following accordingly (acceleration due to gravity $=g$ )

$$ \begin{array}{llll} \hline \text { a. } & \text { Range } & \text { i } & \frac{P}{Q} \\ \hline \text { b. } & \text { Maximum height } & \text { ii } & P \\ \hline \text { c. } & \text { Time of flight } & \text { iii } & \frac{P^2}{4 Q} \\ \hline \text { d. } & \text { Tangent of projection } & \text { iv } & \left(\sqrt{\frac{2}{g Q}}\right) P \\ \hline \end{array} $$

A
a-i,b-iii, c-iv, d-ii
B
a-i, b-iii, c-ii, d-iv
C
a-iii, b-i, c-iv, d-ii
D
a-iv, b-ii, c-iii, d-i

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