1
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

When a galvanometer is shunted by a resistance ' $s$ ', its current capacity increases ' $n$ ' times. If the same galvanometer is shunted by another resistance ' $s_1$ ', its capacity will increase to ' $n_1$ ' times original current. The value of ' $n_1$ ' is

A
$\frac{(\mathrm{n}+\mathrm{s})}{\mathrm{s}_1}$
B
$\frac{s_1(n-s)-s_1}{s_1}$
C
$\frac{(n+1) s}{s_1}$
D
$\frac{\mathrm{s}(\mathrm{n}-1)+\mathrm{s}_1}{\mathrm{~s}_1}$
2
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A pergect gas of volume 5 litre is compressed isothermally to volume of 1 litre. The r.m.s. speed of the molecules will

A
increase by 10 times
B
decrease by 10 times
C
increase by 5 times
D
remain unchanged
3
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

An electron of mass ' $m$ ' and charge ' $q$ ' is accelerated from rest in a uniform electric field of intensity ' $E$ '. The velocity acquired by it as it travels a distance ' $l$ ' is ' $v$ '. The ratio $\frac{\mathrm{q}}{\mathrm{m}}$ in terms of $E, l$ and $v$ is

A
$\frac{\mathrm{v}_2}{2 \mathrm{E} l}$
B
$\frac{\mathrm{v}_2 l}{2 \mathrm{E}}$
C
$\frac{2 \mathrm{E}}{\mathrm{v}^2 l}$
D
$\frac{\mathrm{v}_2 l}{\mathrm{E}}$
4
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a biprism experiment, monochromatic light of wavelength ' $\gamma$ ' is used. The distance between the two coherent sources ' $d$ ' is kept constant. If the distance between slit and eyepiece ' $D$ ' is varied as $D_1, D_2, D_3, D_4$ and corresponding measured fringe widths are $\mathrm{W}_1, \mathrm{~W}_2, \mathrm{~W}_3, \mathrm{~W}_4$ then

A
$\mathrm{W}_1 \mathrm{D}_1=\mathrm{W}_2 \mathrm{D}_2=\mathrm{W}_3 \mathrm{D}_3=\mathrm{W}_4 \mathrm{D}_4$
B
$\frac{\mathrm{W}_1}{\mathrm{D}_1}=\frac{\mathrm{W}_2}{\mathrm{D}_2}=\frac{\mathrm{W}_3}{\mathrm{D}_3}=\frac{\mathrm{W}_4}{\mathrm{D}_4}$
C
$\mathrm{W}_1 \sqrt{\mathrm{D}_1}=\mathrm{W}_2 \sqrt{\mathrm{D}_2}=\mathrm{W}_3 \sqrt{\mathrm{D}_3}=\mathrm{W}_3 \sqrt{\mathrm{D}_3}$
D
$\mathrm{D}_1 \sqrt{\mathrm{~W}_1}=\mathrm{D}_2 \sqrt{\mathrm{~W}_2}=\mathrm{D}_3 \sqrt{\mathrm{~W}_3}=\mathrm{D}_4 \sqrt{\mathrm{~W}_4}$
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