MHT CET 2024 4th May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

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For an entry to a certain course, a candidate is given twenty problems to solve. If the probability that the candidate can solve any problem is $\frac{3}{7}$, then the probability that he is unable to solve at most two problem is

$\frac{256}{49}\left(\frac{4}{7}\right)^{18}$

$\frac{1966}{49}\left(\frac{4}{7}\right)^{18}$

$\frac{1710}{49}\left(\frac{4}{7}\right)^{18}$

$\frac{1726}{49}\left(\frac{4}{7}\right)^{18}$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

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If $\mathrm{A}>\mathrm{B}$ and $\tan \mathrm{A}-\tan \mathrm{B}=x$ and $\cot \mathrm{B}-\cot \mathrm{A}=y$, then $\cot (\mathrm{A}-\mathrm{B})=$

$\frac{1}{y}-\frac{1}{x}$

$\frac{1}{x}-\frac{1}{y}$

$\frac{1}{x}+\frac{1}{y}$

$\frac{x y}{x-y}$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

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Two surfaces A and B are enclosing the charges as shown below. The total normal electric induction (T.N.E.I) through the surfaces A and B are respectively.

MHT CET 2024 4th May Evening Shift Physics - Electrostatics Question 63 English