1
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{A}>\mathrm{B}$ and $\tan \mathrm{A}-\tan \mathrm{B}=x$ and $\cot \mathrm{B}-\cot \mathrm{A}=y$, then $\cot (\mathrm{A}-\mathrm{B})=$

A
$\frac{1}{y}-\frac{1}{x}$
B
$\frac{1}{x}-\frac{1}{y}$
C
$\frac{1}{x}+\frac{1}{y}$
D
$\frac{x y}{x-y}$
2
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two surfaces A and B are enclosing the charges as shown below. The total normal electric induction (T.N.E.I) through the surfaces A and B are respectively.

MHT CET 2024 4th May Evening Shift Physics - Electrostatics Question 60 English

A
$+2 q$ and $+2 q$
B
$+q$ and $+3 q$
C
$+q$ and $+2 q$
D
$+2 q$ and $+3 q$
3
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

An alternating current is given by $\mathrm{I}=100 \sin (50 \pi \mathrm{t})$. How many times will the current become zero in one second?

A
50 times
B
25 times
C
40 times
D
100 times
4
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two bodies ' X ' and ' Y ' at temperatures ' $\mathrm{T}_1$ ' K and ' $T_2$ ' K respectively have the same dimensions. If their emissive powers are same, the relation between their temperatures is

A
$\frac{T_1}{T_2}=\frac{1}{3}$
B
$\frac{\mathrm{T}_1}{\mathrm{~T}_2}=\frac{81}{1}$
C
$\frac{\mathrm{T}_1}{\mathrm{~T}_2}=\frac{3^{\frac{1}{4}}}{1}$
D
$\frac{T_1}{T_2}=\frac{9^{\frac{1}{4}}}{1}$
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