1
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

An electron of mass ' $m$ ' and charge ' $q$ ' is accelerated from rest in a uniform electric field of intensity ' $E$ '. The velocity acquired by it as it travels a distance ' $l$ ' is ' $v$ '. The ratio $\frac{\mathrm{q}}{\mathrm{m}}$ in terms of $E, l$ and $v$ is

A
$\frac{\mathrm{v}_2}{2 \mathrm{E} l}$
B
$\frac{\mathrm{v}_2 l}{2 \mathrm{E}}$
C
$\frac{2 \mathrm{E}}{\mathrm{v}^2 l}$
D
$\frac{\mathrm{v}_2 l}{\mathrm{E}}$
2
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a biprism experiment, monochromatic light of wavelength ' $\gamma$ ' is used. The distance between the two coherent sources ' $d$ ' is kept constant. If the distance between slit and eyepiece ' $D$ ' is varied as $D_1, D_2, D_3, D_4$ and corresponding measured fringe widths are $\mathrm{W}_1, \mathrm{~W}_2, \mathrm{~W}_3, \mathrm{~W}_4$ then

A
$\mathrm{W}_1 \mathrm{D}_1=\mathrm{W}_2 \mathrm{D}_2=\mathrm{W}_3 \mathrm{D}_3=\mathrm{W}_4 \mathrm{D}_4$
B
$\frac{\mathrm{W}_1}{\mathrm{D}_1}=\frac{\mathrm{W}_2}{\mathrm{D}_2}=\frac{\mathrm{W}_3}{\mathrm{D}_3}=\frac{\mathrm{W}_4}{\mathrm{D}_4}$
C
$\mathrm{W}_1 \sqrt{\mathrm{D}_1}=\mathrm{W}_2 \sqrt{\mathrm{D}_2}=\mathrm{W}_3 \sqrt{\mathrm{D}_3}=\mathrm{W}_3 \sqrt{\mathrm{D}_3}$
D
$\mathrm{D}_1 \sqrt{\mathrm{~W}_1}=\mathrm{D}_2 \sqrt{\mathrm{~W}_2}=\mathrm{D}_3 \sqrt{\mathrm{~W}_3}=\mathrm{D}_4 \sqrt{\mathrm{~W}_4}$
3
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The ratio of weight of a man in a stationery lift and weight when the lift is moving downward with a uniform acceleration ' $a$ ' is $3: 2$. Then the value of ' $a$ ' is

A
$\frac{3}{2} g$
B
$\frac{\mathrm{g}}{3}$
C
$\frac{2}{3} \mathrm{~g}$
D
$g$
4
MHT CET 2024 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In series LCR resonant circuit, the capacitance is changed from C to 3 C . To obtain the same resonant frequency, the inductance should be changed from $L$ to

A
$\frac{\mathrm{L}}{3}$
B
$\frac{\mathrm{L}}{2}$
C
$\frac{\mathrm{L}}{\sqrt{3}}$
D
$\mathrm{3 L}$
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