MHT CET 2024 4th May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

The converse of $[p \wedge(\sim q)] \rightarrow r$ is

$\sim \mathrm{r} \rightarrow(\sim \mathrm{p} \vee \mathrm{q})$

$\mathrm{r} \rightarrow(\sim \mathrm{p} \wedge \sim \mathrm{q})$

$(\sim p \vee q) \rightarrow \sim r$

$\mathrm{r} \rightarrow(\mathrm{p} \wedge \mathrm{q})$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

The differential equation obtained by eliminating arbitrary constant from the equation $y^2=(x+c)^3$ is

$\left(\frac{\mathrm{d} y}{\mathrm{~d} x}\right)^3=27 y$

$\left(\frac{\mathrm{d} y}{\mathrm{~d} x}\right)^3=-27 y$

$8\left(\frac{\mathrm{~d} y}{\mathrm{~d} x}\right)^3=27 y$

$ 8\left(\frac{\mathrm{~d} y}{\mathrm{~d} x}\right)^3+27 y=0$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

If the statements $p, q$ and $r$ have the truth values $\mathrm{F}, \mathrm{T}, \mathrm{F}$ respectively, then the truth values of the statement patterns $(p \wedge \sim q) \rightarrow r$ and $(p \vee q) \rightarrow r$ are respectively

$\mathrm{T}, \mathrm{T}$

$\mathrm{T}, \mathrm{F}$

$F, T$

$F, F$

MHT CET 2024 4th May Evening Shift

MCQ (Single Correct Answer)

-0

The decay rate of radium is proportional to the amount present at any time $t$. If initially 60 gms was present and half life period of radium is 1600 years, then the amount of radium present after 3200 years is

20 grams

15 grams

12 grams

10 grams

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