1
GATE EE 2015 Set 2
MCQ (Single Correct Answer)
+2
-0.6
The synchronous generator shown in the figure is supplying active power to an infinite bus via two short, lossless transmission lines, and is initially in steady state. The mechanical power input to the generator and the voltage magnitude E are constant. If one line is tripped at time t1 by opening the circuit breakers at the two ends (although there is no fault), then it is seen that the generator undergoes a stable transient. Which one of the following waveforms of the rotor angle $$\delta $$ shows the transient correctly? GATE EE 2015 Set 2 Power System Analysis - Power System Stability Question 13 English
A
GATE EE 2015 Set 2 Power System Analysis - Power System Stability Question 13 English Option 1
B
GATE EE 2015 Set 2 Power System Analysis - Power System Stability Question 13 English Option 2
C
GATE EE 2015 Set 2 Power System Analysis - Power System Stability Question 13 English Option 3
D
GATE EE 2015 Set 2 Power System Analysis - Power System Stability Question 13 English Option 4
2
GATE EE 2015 Set 2
Numerical
+2
-0
A composite conductor consists of three conductors of radius $$R$$ each. The conductors are arranged as shown below. The geometric mean radius (GMR) (in cm) of the composite conductor is kR. The value of k is ______. GATE EE 2015 Set 2 Power System Analysis - Parameters and Performance of Transmission Lines Question 22 English
Your input ____
3
GATE EE 2015 Set 2
MCQ (Single Correct Answer)
+2
-0.6
For linear time invariant systems, that are Bounded Input Bounded stable, which one of the following statement is TRUE?
A
The impulse response will be integral, but may not be absolutely integrable.
B
The unit impulse response will have finite support.
C
The unit step response will be absolutely integrable.
D
The unit step response will be bounded.
4
GATE EE 2015 Set 2
MCQ (Single Correct Answer)
+2
-0.6
Consider a signal defined by $$$x\left(t\right)=\left\{\begin{array}{l}e^{j10t}\;\;\;for\;\left|t\right|\leq1\\0\;\;\;\;\;\;\;for\;\;\left|t\right|>1\end{array}\right.$$$ Its Fourier Transform is
A
$$\frac{2\sin\left(\omega-10\right)}{\omega-10}$$
B
$$2e^{j10}\frac{\sin\left(\omega-10\right)}{\omega-10}$$
C
$$\frac{2\sin\left(\omega\right)}{\omega-10}$$
D
$$e^{j10\omega\frac{2\sin\omega}\omega}$$
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