1
GATE EE 2015 Set 2
MCQ (Single Correct Answer)
+2
-0.6
A $$3$$-phase transformer rated for $$33 kV/11kV$$ is connected in delta/star as shown in figure. The current transformers $$\left( {C{T_s}} \right)$$ on low and high voltage sides have a ratio of $$500/5.$$ Find the currents $${i_1}$$ and $${i_2}$$, if the fault current is $$300$$ $$A$$ as shown in figure. GATE EE 2015 Set 2 Power System Analysis - Switch Gear and Protection Question 5 English
A
$${i_1} = {1 \over {\sqrt 3 }}A,\,\,{i_2} = 0\,A$$
B
$${i_1} = 0\,A,\,\,{i_2} = 0\,A$$
C
$${i_1} = 0\,A,\,\,{i_2} = {1 \over {\sqrt 3 }}A$$
D
$${i_1} = {1 \over {\sqrt 3 }}A,\,\,{i_2} = {1 \over {\sqrt 3 }}A$$
2
GATE EE 2015 Set 2
MCQ (Single Correct Answer)
+1
-0.3
A $$3$$-bus power system network consists of $$3$$ transmission lines. The bus admittance matrix of the uncompensated system is
$$\left[ {\matrix{ { - j6} & {j3} & {j4} \cr {j3} & { - j7} & {j5} \cr {j4} & {j5} & { - j8} \cr } } \right]\,pu$$
If the shunt capacitance of all transmission lines is $$50$$% compensated, the imaginary part of the $$3$$rd row $$3$$rd column element (in $$pu$$) of the bus admittance matrix after compensation is
A
$$-j7.0$$
B
$$-j8.5$$
C
$$-j7.5$$
D
$$-j9.0$$
3
GATE EE 2015 Set 2
MCQ (Single Correct Answer)
+2
-0.6
For linear time invariant systems, that are Bounded Input Bounded stable, which one of the following statement is TRUE?
A
The impulse response will be integral, but may not be absolutely integrable.
B
The unit impulse response will have finite support.
C
The unit step response will be absolutely integrable.
D
The unit step response will be bounded.
4
GATE EE 2015 Set 2
MCQ (Single Correct Answer)
+2
-0.6
Consider a signal defined by $$$x\left(t\right)=\left\{\begin{array}{l}e^{j10t}\;\;\;for\;\left|t\right|\leq1\\0\;\;\;\;\;\;\;for\;\;\left|t\right|>1\end{array}\right.$$$ Its Fourier Transform is
A
$$\frac{2\sin\left(\omega-10\right)}{\omega-10}$$
B
$$2e^{j10}\frac{\sin\left(\omega-10\right)}{\omega-10}$$
C
$$\frac{2\sin\left(\omega\right)}{\omega-10}$$
D
$$e^{j10\omega\frac{2\sin\omega}\omega}$$
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