AP EAPCET 2024 - 19th May Evening Shift | Haloalkanes and Haloarenes Question 8 | Chemistry

The major product $(X)$ formed in the given reaction is an example of AP EAPCET 2024 - 19th May Evening Shift Chemistry - Haloalkanes and Haloarenes Question 11 English

AP EAPCET 2024 - 19th May Evening Shift Chemistry - Haloalkanes and Haloarenes Question 11 English

secondary alkyl halide

primary alkyl halide

tertiary alkyl halide

benzylic halide

AP EAPCET 2024 - 19th May Evening Shift

MCQ (Single Correct Answer)

-0

Identify the Swarts reaction from the following

AP EAPCET 2024 - 19th May Evening Shift Chemistry - Haloalkanes and Haloarenes Question 12 English Option 1

AP EAPCET 2024 - 19th May Evening Shift Chemistry - Haloalkanes and Haloarenes Question 12 English Option 2

AP EAPCET 2024 - 19th May Evening Shift Chemistry - Haloalkanes and Haloarenes Question 12 English Option 3

AP EAPCET 2024 - 19th May Evening Shift Chemistry - Haloalkanes and Haloarenes Question 12 English Option 4

AP EAPCET 2024 - 18th May Morning Shift

MCQ (Single Correct Answer)

-0

Chlorobenzene ( $X$ ) when reacted with reagent $(A)$ geb converted to phenol $(Y)$. The major product obtained from nitration of $(X)$ gets converted to $p$-nitrophend $(Z)$ by reaction with reagent $(B)$. What are $A$ and $B$ respectively?

$\mathrm{A}=$ (i) $\mathrm{NaOH}, 623 \mathrm{~K}, 300 \mathrm{~atm}$ (ii) $\mathrm{H}^{+} ; B=$ (i) $\mathrm{NaOH}, 443 \mathrm{~K}$ (ii) $\mathrm{H}^{+}$

$A=$ (i) $\mathrm{NaOH}, 443 \mathrm{~K}$ (ii) $\mathrm{H}^{+} ; B=\mathrm{H}_2 \mathrm{O} . \Delta$

$A=$ (i) $\mathrm{NaOH}, 323 \mathrm{~K}$ (ii) $\mathrm{H}^{+}$; $B=$ (i) $\mathrm{NaOH}, 443 \mathrm{~K}$ (ii) $\mathrm{H}^{+}$

$A=$ (i) $\mathrm{NaOH}, 623 \mathrm{~K}, 300 \mathrm{~atm}$ (ii) $\mathrm{H}^{+} ; B=\mathrm{H}_2 \mathrm{O} . \Delta$

AP EAPCET 2024 - 18th May Morning Shift

MCQ (Single Correct Answer)

-0

Match the following reactions with the prodact obtained from them.

List-I	List-II
A Sandmeyer reaction	I $R-I$
B Finkelstein reaction	II $R-\mathrm{F}$
C Swarts reaction	III $\mathrm{Ar}-\mathrm{Br}$
	IV $R-\mathrm{Br}$

$A-$ III, $B-1, C-N$

$A-N, B=1 I, C-1$

$A-111, B-N, C-11$

$\mathrm{A}=$ III, B-L C - II

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