1
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $y=m x+4(m>0)$ is a tangent to the hyperbola $\frac{x^2}{25}-\frac{y^2}{9}=1$, then the point of contact of this tangent is

A

$\left(-\frac{25}{4},-\frac{9}{4}\right)$

B

$\left(\frac{25}{4}, \frac{9}{4}\right)$

C

$(1,5)$

D

$\left(-\frac{1}{2}, \frac{7}{2}\right)$

2
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$P(a \sec \theta, b \tan \theta)$ and $Q(a \sec \phi, b \tan \phi)$ are two points on the hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ where, $\phi+\theta=\frac{\pi}{2}$. If $(h, k)$ is the point of intersection of the normals drawn at $P$ and $Q$, then $k=$

A
$\frac{a^2-b^2}{b}$
B
$\frac{a^2+b^2}{b}$
C
$-\left(\frac{a^2-b^2}{b}\right)$
D
$-\left(\frac{a^2+b^2}{b}\right)$
3
TS EAMCET 2023 (Online) 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If the equation of a hyperbola is $9 x^2-16 y^2+72 x-32 y-16=0$, then the equation of conjugate hyperbola is
A
$9 x^2-16 y^2+72 x-32 y+272=0$
B
$9 x^2-16 y^2+72 x-32 y+288=0$
C
$9 x^2-16 y^2+72 x-32 y-38=0$
D
$9 x^2-16 y^2+72 x-32 y+16=0$
4
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $S$ be the focus of the hyperbola $x^2-2 y^2=1$ lying on the positive $X$-axis. Let $P(-1,1)$ be a given point. Then, the area of the triangle formed by the line $P S$ with the coordinate axes is (in sq. units)

A

$\frac{\sqrt{2}}{2(\sqrt{2}+3)}$

B

$\frac{\sqrt{6}}{2(2+\sqrt{6})}$

C

$\frac{3}{2(2+\sqrt{6})}$

D

$\frac{\sqrt{3}}{2(\sqrt{2}+\sqrt{3})}$

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