1
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The differential equation of the family of all circles of radius ' $a$ ' is

A

$y_1 y_2+\left(1+y_1^2\right)=a$

B

$\left(1+y_1^2\right)^3=a^2 y_2^2$

C

$1+y_1^2=y_2^2+a^2$

D

$y_2^2+1=y_1^2+a^2$

2
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the general solution of $\left(1+y^2\right) d x=\left(\tan ^{-1} y-x\right) d y$ is $x=f(y)+c e^{-\tan ^{-1} y}$, then $f(y)=$

A

$\tan ^{-1} y$

B

$\tan ^{-1} y+1$

C

$\tan ^{-1} y-1$

D

$y \tan ^{-1} y$

3
TG EAPCET 2025 (Online) 4th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $y=f(x)$ is the solution of the differential equation $\left(1+\cos ^2 x\right) f^{\prime}(x)-4 \sin 2 x-f(x) \sin 2 x=0$ when $f(0)=0$, then $f\left(\frac{\pi}{3}\right)=$

A

3

B

$\frac{12}{5}$

C

$\frac{3}{5}$

D

4

4
TG EAPCET 2025 (Online) 4th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The differential equation corresponding to the family of ellipses $\frac{x^2}{a^2}+\frac{y^2}{4}=1$, where ' $a$ ' is an arbitrary constant is

A

$x y \frac{d y}{d x}=4-y^2$

B

$x y \frac{d y}{d x}=4-x^2$

C

$x y \frac{d y}{d x}=x^2-4$

D

$x y \frac{d y}{d x}=y^2-4$

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