Sets and Relations · Mathematics · TS EAMCET

The solution set of the inequation $\sqrt{x^{2}+x-2} > (1-x)$ is

If $A=\left\{x \in R / \sqrt{x^2-8 x+15} \in R\right\}$ and $B=\left\{x \in R / \frac{x-3}{2 x-5}<\frac{x-6}{2 x-11}\right\}$, then $A \cap B=$