1
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$A(2,0), B(0,2), C(-2,0)$ are three points. Let $a, b, c$ be the perpendicular distances from a variable point $P$ on to the lines $A B, B C$ and $C A$ respectively. If $a, b, c$ are in arithmetic progression, then the locus of $P$ is

A

$|\sqrt{2} y|=2|x-y+2|-|x+y-2|$

B

$\sqrt{2}|y|=|x-y+2|-|x+y-2|$

C

$2|x-y+2|=\left|\frac{x+y-2}{\sqrt{2}}\right|+\left|\frac{x-y-2}{\sqrt{2}}\right|$

D

$2|x-y+2|=|x+(\sqrt{2}+1) y+2|$

2
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two families of lines are given by $a x+b y+c=0$ and $4 a^2+9 b^2-c^2-12 a b=0$. Then, the line common to both the families is

A

A line passing through $(-1,2)$ and $(2,3)$

B

A line passing through $(3,2)$ and $(2,3)$

C

A line passing through $(-3,-2)$ and $(-2,-3)$

D

A line passing through $(2,-3)$ and $(-2,3)$

3
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two non-parallel sides of a rhombus are parallel to the lines $x+y-1=0$ and $7 x-y-5=0$. If $(1,3)$ is the centre of the rhombus and one of its vertices $A(\alpha, \beta)$ lies on $15 x-5 y=6$, then one of the possible values of $(\alpha+\beta)$ is

A

$\frac{18}{5}$

B

$\frac{12}{5}$

C

$\frac{37}{5}$

D

$\frac{39}{5}$

4
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the equations $3 x^2+2 h x y-3 y^2=0$ and $3 x^2+2 h x y-3 y^2+2 x-4 y+c=0$ represent the four sides of a square, then $\frac{h}{c}=$

A

$\frac{1}{4}$

B

$\frac{-2}{3}$

C

-3

D

-4

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