1
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the latusrectum of a hyperbola subtends an angle of $120^{\circ}$ at its centre, then its eccentricity is

A

$\frac{\sqrt{3}+2}{\sqrt{2}}$

B

$\frac{\sqrt{3}+\sqrt{5}}{2}$

C

$\frac{\sqrt{3}-\sqrt{2}}{3}$

D

$\frac{\sqrt{3}+\sqrt{7}}{2}$

2
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $P\left(\frac{\pi}{4}\right), Q\left(\frac{5 \pi}{4}\right), R\left(\frac{3 \pi}{4}\right), T\left(\frac{7 \pi}{4}\right)$ be the points on the hyperbola $x^2-4 y^2-4=0$ in the parametric form. Then the area of the quadrilateral $P Q R T$ is (in square units)

A

$4 \sqrt{2}$

B

$16 \sqrt{2}$

C

$32 \sqrt{2}$

D

$8 \sqrt{2}$

3
TS EAMCET 2022 (Online) 18th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the perimeter of a triangle is 20 and two of its vertices are $(-5,0)$ and $(6,0)$, then the locus of the third vertex is

A

$40 x^2-81 y^2-40 x-800=0$

B

$40 x^2+9 y^2-25 x+800=0$

C

$40 x^2-9 y^2=800$

D

$5 x^2-3 y^2+3 x-4 y+25=0$

4
TS EAMCET 2022 (Online) 18th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $S$ be the focus of the hyperbola $\frac{x^2}{16}-\frac{y^2}{9}=1$ lying on the positive $X$ - axis and $P\left(5, y_1\right)$ be point on the hyperbola. Then $S P=$

A

$1 / 4$

B

$3 / 4$

C

$9 / 4$

D

$5 / 4$

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