1
AP EAPCET 2025 - 24th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A body starts from rest with uniform acceleration and its velocity at a time of ' $n$ ' seconds is ' $v$ '. The total displacement of the body in the $n$th and $(n-1)$ th seconds of its motion is

A

$\frac{v(n+1)}{n}$

B

$\frac{2 v(n+1)}{n}$

C

$\frac{2 v(n-1)}{n}$

D

$\frac{v(n-1)}{n}$

2
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If a stone thrown vertically upwards from a bridge with an initial velocity of $5 \mathrm{~ms}^{-1}$, strikes the water below the bridge in a time of 3 s , then the height of the bridge above the water surface is (Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
A

10 m

B

26 m

C

30 m

D

18 m

3
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle moving along a straight line covers the first half of the distance with a speed of $3 \mathrm{~ms}^{-1}$, the other half of the distance is covered in two equal time intervals with speeds of $4.5 \mathrm{~ms}^{-1}$ and $7.5 \mathrm{~ms}^{-1}$ respectively, then the average speed of particle during the motion is

A

$4.0 \mathrm{~ms}^{-1}$

B

$5.0 \mathrm{~ms}^{-1}$

C

$5.5 \mathrm{~ms}^{-1}$

D

$4.8 \mathrm{~ms}^{-1}$

4
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the distance travelled by a freely falling body in the last but one second of its motion is 5 m , then the last second is

(Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )

A

1 st

B

2nd

C

3rd

D

4 th

AP EAPCET Subjects

Browse all chapters by subject