AP EAPCET 2024 - 19th May Evening Shift | Motion in a Straight Line Question 9 | Physics

A car travelling at 80 kmph can be stopped at a distance of 60 m by applying brakes. If the same car travels at 160 kmph and the same braking force is applied, the stopping distance is

240 m

170 m

360 m

480 m

AP EAPCET 2022 - 5th July Morning Shift

MCQ (Single Correct Answer)

-0

A student is at a distance 16 m from a bus when the bus begins to move with a constant acceleration of $$9 \mathrm{~m} \mathrm{~s}^{-2}$$. The minimum velocity with which the student should run. towards the bus so as the catch it is $$\alpha \sqrt{2} \mathrm{~ms}^{-1}$$. The value of $$\alpha$$ is

AP EAPCET 2022 - 4th July Evening Shift

MCQ (Single Correct Answer)

-0

An object moving along $$X$$-axis with a uniform acceleration has velocity $$\mathbf{v}=\left(12 \mathrm{cms}^{-1}\right) \hat{\mathbf{i}}$$ at $$x=3 \mathrm{~cm}$$. After 2 s if it is at $$x=-5 \mathrm{~cm}$$, then its acceleration is

$$\mathbf{a}=\left(-16 \mathrm{~cms}^{-2}\right) \hat{i}$$

$$\mathbf{a}=\left(11 \mathrm{~cms}^{-2}\right) \hat{i}$$

$$\mathbf{a}=\left(-11 \mathrm{~cms}^{-2}\right) \hat{i}$$

$$\mathbf{a}=\left(8 \mathrm{~cms}^{-2}\right) \hat{i}$$

AP EAPCET 2022 - 4th July Evening Shift

MCQ (Single Correct Answer)

-0

$$y=\left(P t^2-Q t^3\right) \mathrm{~m}$$ is the vertical displacement of a ball which is moving in vertical plane. Then the maximum height that the ball can reach is

$$\frac{27 P^3}{4 Q^2}$$

$$\frac{4 Q^2}{27 P^3}$$

$$\frac{4 P^3}{27 Q^2}$$

$$\frac{27 Q^2}{4 P^3}$$

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