$$ \text { The final product }(C) \text { in the given reaction sequence is } $$

$$ \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH} \xrightarrow{\mathrm{SOCl}_2}(A) \xrightarrow[\text { anhy } \cdot \mathrm{AlCl}_3]{\mathrm{C}_6 \mathrm{H}_6}(B) \xrightarrow[\text { (ii) } \mathrm{KOH}_4 /\left(\mathrm{CH}_2 \mathrm{OH}\right)_2]{\text { (i) } \mathrm{NH}_2-\mathrm{NH}_2}(C) $$

An alkyl bromide $X\left(\mathrm{C}_5 \mathrm{H}_{11} \mathrm{Br}\right)$ undergoes hydrolysis in a two step mechanism $X$ is converted to Grignard reagent and then reacted with $\mathrm{CO}_2$ in dry ether followed by acidification gave $Y$. What is $Y$ ?

Consider the following sequence of reactions

$$ \mathrm{C}_6 \mathrm{H}_5 \mathrm{COONa} \xrightarrow[\Delta]{\mathrm{NaOH} / \mathrm{CaO}} X \xrightarrow[\text { Anhy } \cdot \mathrm{AlCl}_3]{\text { CO+ } \mathrm{HCl}} Y \xrightarrow[\text { NaOH }]{\text { Conc. }} A+B $$

If $A$ is the reduction product of $Y$, what is $B$ ?

What are $X, Y, Z$ in the following reaction sequence?

But-2-ene $\xrightarrow{X}$ Ethanoic acid $\xrightarrow{Y}$ Ethanoyl chloride $\xrightarrow[\text { Anhy. } \mathrm{AlCl}_3]{\text { Benzene }} Z$