$$ \text { Benzamide } \xrightarrow{\mathrm{Br}_2 / \mathrm{NaOH}} X \xrightarrow[\text { Alc. } \mathrm{KOH}]{\mathrm{CHCl}_3} Y $$

The conversion of $X$ to $Y$ is

An aryl carboxylic acid on treatment with sodium hydrogen carbonate liberates a gaseous molecule. Identify the gas molecule liberated.

In the presence of peroxide, styrene reacts with HBr to give $$X$$. When $$X$$ is reacted with magnesium in dry ether followed by $$\mathrm{CO}_2$$ and hydrolysis gave $$Y$$. Treatment of Y with $$\mathrm{PCl}_5$$ and then next with $$\mathrm{H}_2$$. $$\mathrm{Pd}-\mathrm{BaSO}_4$$ gave Z . What is Z ?