AP EAPCET 2024 - 23th May Morning Shift | Motion in a Straight Line Question 2 | Physics

A person walks up a stalled escalator in 90 s. When standing on the same moving escalator, he reached in 60s. The time it would take him to walk up the moving escalator will be

36 s

72 s

18 s

27 s

AP EAPCET 2024 - 22th May Evening Shift

MCQ (Single Correct Answer)

-0

A particle starts from rest and moves in a straight line. It travels a distance $2 L$ with uniform acceleration and then moves with a constant velocity a further distance of $L$. Finally, it comes to rest after moving a distance of $3 L$ under uniform retardation. Then, the ratio of average speed to the maximum speed $\left(\frac{v}{v_m}\right)$ of the particle is

$\frac{6}{11}$

$\frac{7}{11}$

$\frac{5}{11}$

$\frac{2}{11}$

AP EAPCET 2024 - 21th May Evening Shift

MCQ (Single Correct Answer)

-0

The velocity of a particle is given by the equation $v(x)=3 x^2-4 x$, where $x$ is the distance covered by the particle. The expression for its acceleration is

$(6 x-4)$

$6\left(3 x^2-4 x\right)$

$\left(3 x^2-4 x\right)(6 x-4)$

$(6 x-4)^2$

AP EAPCET 2024 - 21th May Evening Shift

MCQ (Single Correct Answer)

-0

The acceleration of a particle which moves along the positive $X$-axis varies with its position as shown in the figure. If the velocity of the particle is $0.8 \mathrm{~ms}^{-1}$ at $x=0$ , then its velocity at $x=1.4 \mathrm{~m}$ is $\left(\right.$ in $\left.\mathrm{ms}^{-1}\right)$

AP EAPCET 2024 - 21th May Evening Shift Physics - Motion in a Straight Line Question 4 English

1.6

1.2

1.4

0.8

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