An op-amp, having a slew rate of $$62.8$$ $$V/\mu \,$$sec, is connected in a voltage follower configuration. If the maximum amplitude of the input sinusoidal is $$10$$ Volts. Then the minimum frequency at which the slew rate limited distortion would set in at the output is

For the oscillator circuit shown in figure, the expression for the time period of oscillations can be given by (where $$\tau = RC$$ )

An op-amp has an open-loop gain of $${10^5}$$ and an open-loop upper cutoff frequency of $$10$$ $$Hz.$$ If this op-amp is connected as an amplifier with a closed-loop gain of $$100,$$ then the new upper cutoff frequency is

For the op-amp circuit shown in figure. Determine the output voltage $${v_0}.$$ Assume that the op-amps are ideal