1
GATE EE 1998
Subjective
+5
-0
Show that the circuit given in fig. will work as an oscillator at $$f = {1 \over {2\pi RC}},$$ if $${R_1} = 2{R_2}$$
2
GATE EE 1998
MCQ (Single Correct Answer)
+2
-0.6
For block diagram shown in Figure $$C(s)/R(s)$$ is given by
A
$${{{G_1}{G_2}{G_3}} \over {1 + {H_2}{G_2}{G_3} + {H_1}{G_1}{G_2}}}$$
B
$${{{G_1}{G_2}{G_3}} \over {1 + {G_1}{G_2}{G_3} + {H_1}{H_2}}}$$
C
$${{{G_1}{G_2}{G_3}} \over {1 + {G_1}{G_2}{G_3}{H_1} + {G_1}{G_2}{G_3}{H_2}}}$$
D
$${{{G_1}{G_2}{G_3}} \over {1 + {G_1}{G_2}{G_3}{H_1}}}$$
3
GATE EE 1998
MCQ (Single Correct Answer)
+1
-0.3
The output of a linear time invariant control system is $$c(t)$$ for a certain input $$r(t).$$ If $$r(t)$$ is modified by passing it through a block whose transfer function is $${e^{ - s}}$$ and then applied to the system, the modified output of the system would be
A
$${{c\left( t \right)} \over {1 + {e^t}}}$$
B
$${{c\left( t \right)} \over {1 + {e^{ - t}}}}$$
C
$$c\left( {t - 1} \right)u\left( {t - 1} \right)$$
D
$$c\left( t \right)\,\,u\left( {t - 1} \right)$$
4
GATE EE 1998
MCQ (Single Correct Answer)
+1
-0.3
None of the poles of a linear control system lie in the right half of $$s$$-plane. For a bounded input, the output of this system
A
is always bounded
B
could be unbounded
C
always tends to zero
D
None of the above
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