1
AP EAPCET 2022 - 5th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two wires $$A$$ and $$B$$ of same cross-section are connected end to end. When same tension is created in both wires, the elongation in $$B$$ wire is twice the elongation in $$A$$ wire. If $$L_A$$ and $$L_B$$ are the initial lengths of the wires $$A$$ and $$B$$ respectively, then (Young's modulus of material of wire $$A=2 \times 10^{11} \mathrm{~Nm}^{-2}$$ and Young's modulus of material of wire $$B=1.1 \times 10^{11} \mathrm{~Nm}^{-2}$$).

A
$$\frac{L_A}{L_B}=\frac{10}{11}$$
B
$$\frac{L_A}{L_B}=\frac{4}{5}$$
C
$$\frac{L_A}{L_B}=\frac{9}{11}$$
D
$$\frac{L_A}{L_B}=\frac{3}{7}$$
2
AP EAPCET 2022 - 4th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

Same tension is applied to the following four wires made of same material. The elongation is longest in

A
wire of length 200 cm and diameter 2 mm
B
wire of length 300 cm and diameter 3 mm
C
wire of length 50 cm and diameter 0.5 mm
D
wire of length 100 cm and diameter 1 mm
3
AP EAPCET 2021 - 19th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

Young's modulus of a wire is $$2 \times 10^{11} \mathrm{Nm}^{-2}$$. If an external stretching force of $$2 \times 10^{11} \mathrm{~N}$$ is applied to a wire of length $$L$$. The final length of the wire is (cross-section = unity)

A
2 L
B
1.5 L
C
3 L
D
1.25 L
4
AP EAPCET 2021 - 19th August Morning Shift
MCQ (Single Correct Answer)
+1
-0

The Young's modulus of a rubber string of length $$12 \mathrm{~cm}$$ and density $$1.5 ~\mathrm{kgm}^{-3}$$ is $$5 \times 10^8 ~\mathrm{Nm}^{-2}$$. When this string is suspended vertically, the increase in its length due to its own weight is (Take, $$g=10 \mathrm{~ms}^{-2}$$ )

A
$$2.16 \times 10^{-10} \mathrm{~m}$$
B
$$9.6 \times 10^{-11} \mathrm{~m}$$
C
$$9.6 \times 10^{-3} \mathrm{~m}$$
D
$$2.16 \times 10^{-3} \mathrm{~m}$$
AP EAPCET Subjects
EXAM MAP