1
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a series resonant LCR circuit, for the power dissipated to become half of the maximum power dissipated, the current amplitude is

A

$\frac{1}{\sqrt{2}}$ times its maximum value.

B

$1 / 2$ times its maximum value.

C

twice its maximum value.

D

$\sqrt{2}$ times its maximum value.

2
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If a resistor of resistance $4 \Omega$, a capacitor of capacitive reactance $6 \Omega$ and an inductor of inductive reactance $9 \Omega$ are connected in series with an AC source, then the impedance of the circuit is

A

$19 \Omega$

B

$11 \Omega$

C

$7 \Omega$

D

$5 \Omega$

3
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A resistor of $450 \Omega$ and an inductor are connected in series to an AC source of frequency $\frac{75}{\pi} \mathrm{~Hz}$. If the power factor of the circuit is 0.6 , then the inductance connected in the circuit is

A

6 mH

B

4 H

C

4 mH

D

6 H

4
AP EAPCET 2025 - 22nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

For better tuning of a series $L C R$ circuit in a communication system, the preferred combination is

A

$R=20 \Omega: L=15 \mathrm{H}: \mathrm{C}=35 \mu \mathrm{~F}$

B

$R=15 \Omega: L=40 \mathrm{H}: \mathrm{C}=20 \mu \mathrm{~F}$

C

$R=25 \Omega: L=15 \mathrm{H}: C=45 \mu \mathrm{~F}$

D

$R=15 \Omega: L=20 \mathrm{H}: C=45 \mu \mathrm{~F}$

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