1
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If a straight current carrying wire of linear density $0.12 \mathrm{~kg} \mathrm{~m}^{-1}$ is suspended in mid air by a uniform horizontal magnetic field of 0.5 T normal to the length of the wire, then the current through the wire is (Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$, Neglect Earth's magnetic field)

A

2.4 A

B

1.2 A

C

0.6 A

D

4.8 A

2
AP EAPCET 2025 - 21st May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two concentric loops $A$ and $B$ of same radius $2 \pi \mathrm{~cm}$ are placed at right angles to each other. If the currents flowing through $A$ and $B$ are 3 A and 4 A respectively, then the net magnetic field at their common centre is

A

$0.75 \times 10^{-5} \mathrm{~T}$

B

$25 \times 10^{-5} \mathrm{~T}$

C

$5 \times 10^{-5} \mathrm{~T}$

D

$2.5 \times 10^{-5} \mathrm{~T}$

3
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The magnetic field at a distance of 10 cm from a long straight thin wire carrying a current of 4 A is

A

$6 \mu \mathrm{~T}$

B

$16 \mu \mathrm{~T}$

C

$8 \mu \mathrm{~T}$

D

$4 \mu T$

4
AP EAPCET 2025 - 21st May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A velocity selector is to be constructed to select ions with a velocity of $6 \mathrm{~km} \mathrm{~s}^{-1}$. If the electric field used is $400 \mathrm{~V} \mathrm{~m}^{-1}$, then the magnetic field to be used is

A

$\frac{11}{20} T$

B

$\frac{2}{3} T$

C

$\frac{1}{15} \mathrm{~T}$

D

$\frac{2}{15} \mathrm{~T}$

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