Both statement-I and statement-II are correct.

Both statement-I and statement-II are not correct.

Statement-I is correct, but statement-II is not correct.

Statement-I is not correct, but statement-II is correct.

Glucose does not give Schiff's test.

Glucose exists in two crystalline forms $\alpha$ - and $\beta$ -

The pentaacetate of glucose does not react with $\mathrm{NH}_2 \mathrm{OH}$.

Glucose forms addition product with $\mathrm{NaHSO}_3$.

Proteins → Peptides (pepsin)

Starch → Maltose (Zymase)

Sucrose → Glucose and Fructose (Invertase)

Maltose → Glucose (Maltase)