1
AP EAPCET 2025 - 23rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Adsorption of a gas on solids follows Freundlich adsorption isotherm. The graph drawn between $\log \frac{x}{m}$ (on $y$-axis) and $\log p$ (on $x$-axis) is a straight line with slope equal to 3 and intercept equal to 0.30 . What is the value of $\frac{x}{m}$ at a pressure of 2 atm ?

(Given: $\log 2=0.3$ )

A

48

B

32

C

16

D

8

2
AP EAPCET 2025 - 23rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The adsorption of a gas on a solid surface follows Freundlich adsorption isotherm. At $T(\mathrm{~K})$, the gas pressure is 2 atm . What is the value of $\frac{x}{m} ?(n=2$ and $k=$ constant $)$
A

$\frac{x}{m}=4 k$

B

$\frac{x}{m}=\frac{1.414}{k}$

C

$\frac{x}{m}=\frac{k}{1.414}$

D

$\frac{x}{m}=1.414 k$

3
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a colloidal solution, both the dispersed phase and dispersion medium are in liquid phase. What is the type of colloid?

A

Gel

B

Emulsion

C

Foam

D

Aerosol

4
AP EAPCET 2025 - 22nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The equation which represents Freundlich adsorption isotherm is ( $x=$ amount of gas, $m=$ mass of solid)

A

$\log \frac{x}{m}=\log p+\frac{1}{n} \log k$

B

$\log \frac{x}{m}=\log k+\frac{1}{n} \log p$

C

$\frac{x}{m}=k+\frac{1}{n} \log p$

D

$\frac{x}{m}=\log p+\frac{1}{n} \log k$

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