AP EAPCET 2024 - 20th May Morning Shift | Wave Optics Question 4 | Physics

In Young's double slit experiment two slits are placed 2 mm from each other. Interference pattern is observed on a screen placed 2 m from the plane of the slits. Then the fringe width for a light of wavelength 400 nm is

$0.4 \times 10^{-6} \mathrm{~m}$

$4 \times 10^{-6} \mathrm{~m}$

$0.4 \times 10^{-3} \mathrm{~m}$

400 m

AP EAPCET 2024 - 19th May Evening Shift

MCQ (Single Correct Answer)

-0

In Young's double slit experiment, the intensity at a point where the path difference is $\frac{\lambda}{6}$ ( $\lambda$ being the wavelength of the light used) is $I$. If $I_0$ denotes the maximum intensity, $\frac{I}{I_0}$ is equal to

$\frac{1}{\sqrt{2}}$

$\frac{\sqrt{3}}{2}$

$\frac{1}{2}$

$\frac{3}{4}$

AP EAPCET 2024 - 18th May Morning Shift

MCQ (Single Correct Answer)

-0

In Young's double slit experiment with monochromatic light of wavelength 6000 A . The fringe width is 3 mm . If the distance between the screen and slits is increased by $50 \%$ and the distance between the slits is decreased by $10 \%$, then the fringe width is

12 mm

5 mm

6 mm

10 mm

AP EAPCET 2022 - 5th July Morning Shift

MCQ (Single Correct Answer)

-0

Young's double slit experiment is conducted with monochromatic light of wavelength 5000$$\mathop A\limits^o $$, with slit separation of 3 mm and observer at 20 cm away from the slits. If a 1 mm transparent plate is placed infront of one of the slits, the fringes shift by 6 mm . The refractive index of the transparent plate is

1.08

1.09

1.1

1.2

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