1
AP EAPCET 2024 - 21th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If the time period of revolution of a satellite is $T$, the its kinetic energy is proportional to
A
$T^{-1}$
B
$T^{-2}$
C
$T^{-3}$
D
$T^{-2 / 3}$
2
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
What is the height from the surface of earth, where acceleration due to gravity will be $1 / 4$ of that of the earth? $\left(R_E=6400 \mathrm{~km}\right)$
A
6400 km
B
3200 km
C
1600 km
D
640 km
3
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The acceleration due to gravity at a height of 6400 km from the surface of the earth is $2.5 \mathrm{~ms}^{-2}$. The acceleration due to gravity at a height of 12800 km from the surface of the earth is (Radius of the earth= 6400 km )
A
$1.11 \mathrm{~ms}^{-2}$
B
$1.5 \mathrm{~ms}^{-2}$
C
$2.22 \mathrm{~ms}^{-2}$
D
$1.25 \mathrm{~ms}^{-2}$
4
AP EAPCET 2024 - 19th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
Maximum height reached by a rocket fired with a speed equal to $50 \%$ of the escape speed from the surface of the earth is ( $R=$ Radius of the earth)
A
$\frac{R}{2}$
B
$\frac{16 R}{9}$
C
$\frac{R}{3}$
D
$\frac{R}{8}$
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