AP EAPCET 2024 - 22th May Morning Shift | Gravitation Question 3 | Physics

A satellite moving round the earth in a circular orbit has kinetic energy $E$. Then, the minimum amount of energy to be added so that it escapes from the earth.

$\frac{E}{4}$

$E$

$\frac{E}{2}$

$2 F$

AP EAPCET 2024 - 21th May Evening Shift

MCQ (Single Correct Answer)

-0

A particle is projected from the surface of the earth with a velocity equal to twice the escape velocity. When particle is very far from the earth. Its speed would be

$v_e$

$2 v_e$

$\sqrt{3} v_e$

$\sqrt{2} v_e$

AP EAPCET 2024 - 21th May Morning Shift

MCQ (Single Correct Answer)

-0

The time period of revolution of a satellite $T$ around the carth depends on the radius of the circular orbit $R$. mass of the earth $M$ and universal gravitational constant $G$. The expression for $T$, using dimensional analysis is ( $K$ is constant of proportionality)

$K \sqrt{\frac{R^2}{G M}}$

$K \sqrt{\frac{R}{G M}}$

$K \sqrt{\frac{R^3}{G M}}$

$K \sqrt{\frac{R^3}{G M^2}}$

AP EAPCET 2024 - 21th May Morning Shift

MCQ (Single Correct Answer)

-0

If the time period of revolution of a satellite is $T$, the its kinetic energy is proportional to

$T^{-1}$

$T^{-2}$

$T^{-3}$

$T^{-2 / 3}$

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