1
AP EAPCET 2024 - 21th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Given below are two statements.

Statement I : Liquids $A$ and $B$ form a non-ideal solution with negative deviation. The interactions between $A$ and $B$ are weaker than $A-A$ and $B-B$ interactions.

Statement II : In reverse osmosis, the applied pressure must be higher than the osmotic pressure of solution

The correct answer is

A
Both Statement I and Statement II are correct.
B
Both Statement I and Statement II are not correct.
C
Statement I is correct but Statement II is not correct.
D
Statement I is not correct but Statement II is correct
2
AP EAPCET 2024 - 21th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
A solution was prepared by dissolving 0.1 mole of a non- volatile solute in 0.9 moles of water. What is the relative lowering of vapour pressure of solution?
A
0.9
B
0.5
C
0.1
D
0.05
3
AP EAPCET 2024 - 20th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A non- volatile solute is dissolved in water. The $\Delta T_{\mathrm{b}}$ of resultant solution is 0.052 K . What is the freezing point of the solution ( in K )?

( $K_b$ of water $=0.52 \mathrm{~K} \mathrm{kgmol}^{-1}$,

$K_f$ of water $=1.86 \mathrm{~K} \mathrm{kgmol}^{-1}$,

freezing point of water $=273 \mathrm{~K}$ )

A
272.628
B
273.186
C
273.000
D
272.814
4
AP EAPCET 2024 - 20th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The osmotic pressure of sea water is 1.05 atm . Four experiments were carried as shown in table. In which of the following experiments, pure water can be obtained in part-II of vessel.

AP EAPCET 2024 - 20th May Morning Shift Chemistry - Liquid Solution Question 12 English $$ \begin{aligned} &\text { Table }\\ &\begin{array}{ccc} \hline \begin{array}{c} \text { Expt. } \\ \text { No } \end{array} & \begin{array}{c} \text { Pressure applied in } \\ \text { part-1 of vessel } \end{array} & \begin{array}{c} \text { Pressure applied in } \\ \text { part-II of vessel } \end{array} \\ \hline \text { I. } & 10 \mathrm{~atm} & - \\ \hline \text { II. } & - & 10 \mathrm{~atm} \\ \hline \text { III. } & 15 \mathrm{~atm} & - \\ \hline \text { IV. } & - & 15 \mathrm{~atm} \end{array} \end{aligned} $$
A
I, III only
B
II, IV only
C
I, II, III, IV
D
IV only
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