Given below are two statements.
Statement I : Liquids $A$ and $B$ form a non-ideal solution with negative deviation. The interactions between $A$ and $B$ are weaker than $A-A$ and $B-B$ interactions.
Statement II : In reverse osmosis, the applied pressure must be higher than the osmotic pressure of solution
The correct answer is
A non- volatile solute is dissolved in water. The $\Delta T_{\mathrm{b}}$ of resultant solution is 0.052 K . What is the freezing point of the solution ( in K )?
( $K_b$ of water $=0.52 \mathrm{~K} \mathrm{kgmol}^{-1}$,
$K_f$ of water $=1.86 \mathrm{~K} \mathrm{kgmol}^{-1}$,
freezing point of water $=273 \mathrm{~K}$ )
The osmotic pressure of sea water is 1.05 atm . Four experiments were carried as shown in table. In which of the following experiments, pure water can be obtained in part-II of vessel.
$$
\begin{aligned}
&\text { Table }\\
&\begin{array}{ccc}
\hline \begin{array}{c}
\text { Expt. } \\
\text { No }
\end{array} & \begin{array}{c}
\text { Pressure applied in } \\
\text { part-1 of vessel }
\end{array} & \begin{array}{c}
\text { Pressure applied in } \\
\text { part-II of vessel }
\end{array} \\
\hline \text { I. } & 10 \mathrm{~atm} & - \\
\hline \text { II. } & - & 10 \mathrm{~atm} \\
\hline \text { III. } & 15 \mathrm{~atm} & - \\
\hline \text { IV. } & - & 15 \mathrm{~atm}
\end{array}
\end{aligned}
$$