AP EAPCET 2024 - 20th May Evening Shift | Fluid Mechanics Question 6 | Physics

Depth of a river is 100 m magnitude of compressibility of the water is $05 \times 10^{-9} \mathrm{~N}^{-1} \mathrm{~m}^2$. The fractional compression in water at the bottom of the river is (acceleration due to gravity $=10 \mathrm{~m} / \mathrm{s}^2$ )

$0.9 \times 10^3$

$0.5 \times 10^{-3}$

$2 \times 10^{-3}$

$1.3 \times 10^{-2}$

AP EAPCET 2024 - 20th May Evening Shift

MCQ (Single Correct Answer)

-0

Two mercury drops, each with same radius $r$ merged to form a bigger drop. $T$ is the surface tension of single drop, then the surface energy of bigger drop is given by

$2 \pi r^2 T$

$2^{\frac{5}{3}} \pi r^2 T$

$2 \pi r^2 T^2$

$2^{\frac{8}{3}} \pi r^2 T$

AP EAPCET 2024 - 20th May Morning Shift

MCQ (Single Correct Answer)

-0

The radius of cross-section of the cylindrical tube of a spray pump is 2 cm . One end of the pump has 50 fine holes each of radius 0.4 mm . If the speed of flow of the liquid inside the tube is $0.04 \mathrm{~ms}^{-2}$. The speed of ejection of the liquid from the holes is

$6 \mathrm{~ms}^{-1}$

$2 \mathrm{~ms}^{-1}$

$4 \mathrm{~ms}^{-1}$

$3 \mathrm{~ms}^{-1}$

AP EAPCET 2024 - 19th May Evening Shift

MCQ (Single Correct Answer)

-0

If $S_1, S_2$ and $S_3$ are the tensions at liquid-air, solid-air and solid-liquid interfaces respectively and $\theta$ is the angle of contact at the solid-liquid interface, then

$S_1 \cos \theta+S_2 \sin \theta=S_3$

$S_1 \cos \theta+S_3=S_2$

$S_2 \cos \theta+S_3=S_1$

$S_3 \cos \theta+S_1=S_2$

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