AP EAPCET 2024 - 20th May Morning Shift | Dual Nature of Radiation Question 7 | Physics

An electron of mass $m$ with initial velocity $\mathbf{v}=v_0 \hat{\mathbf{i}}\left(v_0>0\right)$ enters in an electric field $\mathbf{E}=-E_0 \hat{\mathbf{i}}$ ( $E_0$ is constant $>0$ ) at $t=0$. If $\lambda$ is its de-Broglie wavelength initially, then the de-Broglie wavelength after time $t$ is

$\frac{\lambda}{1+\frac{e E_d}{m v_0}}$

$\frac{\lambda}{\left(1-\frac{e E_d}{m v_0}\right)^2}$

$\left(1+\frac{e E_\alpha}{m v_0}\right) \lambda$

$\left(1+\frac{e E_d}{m v_0}\right)^2 \lambda$

AP EAPCET 2024 - 19th May Evening Shift

MCQ (Single Correct Answer)

-0

The longest wavelength of light that can initiate photo electric effect in the metal of work function 9 eV is

$1.37 \times 10^{-7} \mathrm{~m}$

$1.5 \times 10^{-7} \mathrm{~m}$

$3.7 \times 10^{-7} \mathrm{~m}$

$4 \times 10^{-7} \mathrm{~m}$

AP EAPCET 2024 - 18th May Morning Shift

MCQ (Single Correct Answer)

-0

Energy required to remove an electron from aluminium surface is 4.2 eV . If light of wavelength $2000 \mathring{A}$ falls on the surface, the velocity of the fastest ejected electron the surface will be

$84 \times 10^5 \mathrm{~ms}^{-1}$

$7.4 \times 10^6 \mathrm{~ms}^{-1}$

$64 \times 10^5 \mathrm{~ms}^{-1}$

$84 \times 10^6 \mathrm{~ms}^{-1}$

AP EAPCET 2022 - 5th July Morning Shift

MCQ (Single Correct Answer)

-0

The following statement is correct in the case of photoelectric effect

For a given frequency of incident radiation, the stopping potential varies linearly with its intensity.

For a given frequency of incident radiation, the photocurrent is independent of its intensity.

For a given frequency of a incident radiation, the maximum kinetic energy of the photoelectrons is independent of its intensity.

For a frequency lower than cutoff frequency, photoelectric emissions can occur if intensity of incident light is increased slightly.

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