A 10 L vessel contains 1 mole of an ideal gas with pressure of $p(\mathrm{~atm})$ and temperature of $T(\mathrm{~K})$. The vessel is divided into two equal parts. The pressure (in atm) and temperature in (K) in each part is respectively.

At $T(\mathrm{~K})$ for one mole of an ideal gas, the graph of $p$ (on $Y$-axis) and $V^{-1}$ (on $X$-axis) gave a straight line with slope of $32.8 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1}$. What is the temperature (in K$) ?\left(R=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)$

A vessel of volume $V \mathrm{~L}$ contains an ideal gas are $T(\mathrm{~K})$. The vessel is partitioned into two equal parts. The volume (in L ) and temperature (in K ) in each part is respectively.

At 240.55 K , for one mole of an ideal gas, a graph of $p$ (on $Y$-axis) and $V^{-1}$ (on $X$-axis) gave a straight line passing through origin. Its slope $(m)$ is $2000 \mathrm{~J} \mathrm{~mol}^{-1}$. What is the kinetic energy ( in $\mathrm{J} \mathrm{mol}^{-1}$ ) of ideal gas?