1
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The length of the perpendicular from the point $\mathrm{A}(1,-2,-3)$ on the line $\frac{x-1}{2}=\frac{y+3}{-1}=\frac{z+1}{-2}$ is

A
6 units
B
3 units
C
2 units
D
4 units
2
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The straight line, $2 x-3 y+17=0$ is perpendicular to the line passing through the points $(7,17)$ and $(15, \beta)$, then $\beta$ equals

A
$5$
B
$\frac{35}{3}$
C
$-\frac{35}{3}$
D
$-5$
3
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{f}(x)=\frac{x^2-x}{x^2+2 x}$ then $\frac{\mathrm{d}}{\mathrm{d} x}\left(\mathrm{f}^{-1}(x)\right)$ at $x=2$ is

A
$-3$
B
3
C
$-1$
D
1
4
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

For the triangle ABC , with usual notations, if the angles $A, B, C$ are in A.P. and $\mathrm{m} \angle \mathrm{A}=30^{\circ}, \mathrm{c}=3$, then the values of a and b are respectively

A
$\frac{\sqrt{3}}{2}, \frac{3}{2}$
B
$\frac{3}{2}, \frac{3 \sqrt{3}}{2}$
C
$\frac{3 \sqrt{3}}{2}, \frac{3}{2}$
D
$\frac{3}{2}, \frac{\sqrt{3}}{2}$
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