1
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A point object kept at P in front of a glass sphere of radius ' $R$ ' has its image formed at $Q$ such that $\mathrm{PO}=\mathrm{QO}$. The refractive index of material of glass sphere is 1.4. The distance PO is equal to

MHT CET 2024 9th May Morning Shift Physics - Ray Optics Question 5 English

A
$\frac{\mathrm{R}}{2}$
B
2R
C
5R
D
6R
2
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The magnetic flux through a coil of resistance ' $R$ ' changes by an amount ' $\Delta \phi$ ' in time ' $\Delta t$ '. The amount of induced current and induced charge in the coil are respectively

A
$\left(\frac{\Delta \phi}{\Delta t}\right) R$ and $\frac{R}{\Delta \phi}$
B
  $\frac{\Delta \phi}{\mathrm{R}}$ and $\mathrm{R}\left(\frac{\Delta \mathrm{t}}{\Delta \phi}\right)$
C
$\frac{\Delta \phi}{\mathrm{R}}+\mathrm{R}$ and $\frac{\Delta \phi}{\Delta \mathrm{t}}$
D
$\left(\frac{\Delta \phi}{\Delta \mathrm{t}}\right) \times \frac{1}{\mathrm{R}}$ and $\frac{\Delta \phi}{\mathrm{R}}$
3
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A circular disc of radius ' $R$ ' and thickness $\frac{R}{8}$ has moment of inertia 'I' about an axis passing through its centre and perpendicular to its plane. It is melted and recasted into a solid sphere then moment of inertia of sphere about an axis passing through diameter is

A
$I$
B
$\frac{21}{3}$
C
$\frac{\mathrm{I}}{5}$
D
$\frac{\mathrm{I}}{10}$
4
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

When the two known resistance ' $R$ ' and ' $S$ ' are connected in the left and right gaps of a meter bridge respectively, the null point is found at a distance ' $l_1$ ' from the zero end of a meter bridge wire. An unknown resistance ' X ' is now connected in parallel with ' S ' and null point is found at a distance ' $l_2$ ' form zero end of meter bridge wire. The unknown resistance ' X ' is

A
$\frac{\mathrm{S} l_1\left(100-l_2\right)}{100\left(l_2-l_1\right)}$
B
$\frac{\mathrm{S} l_2\left(100-l_1\right)}{100\left(l_1-l_2\right)}$
C
$\frac{100\left(l_2-l_1\right)}{\mathrm{Sl}_1\left(100-l_2\right)}$
D
$\frac{100\left(l_2-l_1\right)}{\mathrm{S} l_2\left(100-l_1\right)}$
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