1
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Find the percentage of unreacted reactant for zero order reaction in 90 second having rate constant $1 \mathrm{~mol} \mathrm{~dm}^{-3} \mathrm{~s}^{-1}$.

A
5%
B
10%
C
15%
D
20%
2
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $A=\left[\begin{array}{lll}1 & 1 & 1 \\ 1 & a & 3 \\ 3 & 2 & 2\end{array}\right]$ and $B=\left[\begin{array}{ccc}-2 & 0 & b \\ 7 & -1 & -2 \\ c & 1 & 1\end{array}\right]$ and if matrix $B$ is the inverse of matrix $A$, then value of $4 a+2 b-c$ is

A
6
B
$-$14
C
14
D
$-$6
3
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\int \mathrm{f}(x) \mathrm{d} x=\psi(x)$, then $\int x^5 \mathrm{f}\left(x^3\right) \mathrm{d} x$ is equal to

A
$\frac{1}{3} x^3 \psi\left(x^3\right)-3 \int x^3 \psi\left(x^3\right) \mathrm{d} x+\mathrm{c}$, (where c is a constant of integration)
B
$\frac{1}{3}\left(x^3 \psi\left(x^3\right)-\int x^3 \psi\left(x^3\right) \mathrm{d} x\right)+\mathrm{c}$, (where c is a constant of integration)
C
$\frac{1}{3} x^3 \psi\left(x^3\right)-\int x^2 \psi\left(x^3\right) \mathrm{d} x+\mathrm{c}$, (where c is a constant of integration)
D
$\frac{1}{3}\left(x^3 \psi\left(x^3\right)-\int x^2 \psi\left(x^3\right) \mathrm{d} x\right)+\mathrm{c}$, (where c is a constant of integration)
4
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The population of a town increases at a rate proportional to the population at that time. If the population increases from 40 thousand to 80 thousand in 40 years, then the population in another 40 years will be

A
180000
B
128000
C
160000
D
256000
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