1
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A particle is performing S.H.M. with an amplitude 4 cm . At the mean position the velocity of the particle is $12 \mathrm{~cm} / \mathrm{s}$. When the speed of the particle becomes $6 \mathrm{~cm} / \mathrm{s}$, the distance of the particle from mean position is

A
$\sqrt{3} \mathrm{~cm}$
B
$\sqrt{6} \mathrm{~cm}$
C
$2 \sqrt{3} \mathrm{~cm}$
D
$2 \sqrt{6} \mathrm{~cm}$
2
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A velocity - time graph of a body is shown below. The distance covered by the body from 6 second to 9 second is

MHT CET 2024 9th May Morning Shift Physics - Motion Question 20 English

A
22.5 m
B
60.0 m
C
82.5 m
D
120.0 m
3
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two identical photocathodes receive light of frequencies ' $\mathrm{n}_1$ ' and ' $\mathrm{n}_2$ '. If the velocities of the emitted photoelectrons of mass ' $m$ ' are ' $\mathrm{V}_1$ ' and ' V , respectively, then ( $\mathrm{h}=$ Planck's constant )

A
$\mathrm{V}_1+\mathrm{V}_2=\left[\frac{2 \mathrm{~h}}{\mathrm{~m}}\left(\mathrm{n}_1+\mathrm{n}_2\right)\right]^{1 / 2}$
B
$\mathrm{V}_1-\mathrm{V}_2=\left[\frac{2 \mathrm{~h}}{\mathrm{~m}}\left(\mathrm{n}_1-\mathrm{n}_2\right)\right]^{1 / 2}$
C
$\mathrm{V}_1^2+\mathrm{V}_2^2=\frac{2 \mathrm{~h}}{\mathrm{~m}}\left(\mathrm{n}_1+\mathrm{n}_2\right)$
D
$\mathrm{V}_1^2-\mathrm{V}_2^2=\frac{2 \mathrm{~h}}{\mathrm{~m}}\left(\mathrm{n}_1-\mathrm{n}_2\right)$
4
MHT CET 2024 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The temperature of a gas is $-80^{\circ} \mathrm{C}$. To what temperature the gas should be heated so that the r.m.s. speed is increased by 2 times?

A
$499^{\circ} \mathrm{C}$
B
$772^{\circ} \mathrm{C}$
C
$1464^{\circ} \mathrm{C}$
D
$1737^{\circ} \mathrm{C}$
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